Question

a television game show has 4 doors of which contestant must pick two. behind two of the doors are expensive cars and behind the other 2 doors are consolation prizes. find the probability that the contestant wins both cars, no cars, or at least 1 car

Answer 1

both cars
\[\frac{2}{4}\times \frac{1}{3}\]

Answer 2

no cars is the same
\[\frac{1}{6}\]

Answer 3

at least one car is
\[1-\frac{1}{6}=\frac{5}{6}\]