Question

Is there a solution to the following equation on the interval 0 (less than or equal to) theta < (2pi)?

sin(2theta)=-(sqrt3)/2

Answer 1

\[2\theta=n \pi-(-1)^n \pi/6\]

Answer 2

The angles that generate that sin value are \[4\pi/3\]\[5\pi/3\]

Answer 3

Ok and which of the two angles do I use in order to solve the equation?

Answer 4

So the values of x that will work are\[2\pi/3\]\[5\pi/6\]

Answer 5

Sorry, theta, not x.