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Mathematics 62 Online
OpenStudy (anonymous):

A bank account earns 10% interest compounded continuously. At what (constant, continuous) rate must a parent deposit money into such an account in order to save $100,000 in 10 years for a child's college expenses

OpenStudy (amistre64):

whew!! you never know where those things take you

OpenStudy (amistre64):

A = Pe^(rt) is our compunding continuously formula

OpenStudy (anonymous):

right but you have to do it backwards to find what to put in annually

OpenStudy (amistre64):

do we start at 0?

OpenStudy (anonymous):

yes zero to 10

OpenStudy (anonymous):

the answer in the back of my book is 5820 per year

OpenStudy (amistre64):

A=Pert is positon, our amount at a given time A' = rate at which it changes

OpenStudy (amistre64):

A' = Pr e^{rt}

OpenStudy (anonymous):

i believe its e to the negative rt right?

OpenStudy (amistre64):

no, but why would you think that?

OpenStudy (amistre64):

-rt is losing money

OpenStudy (anonymous):

well our present value formula is the integral of P(t)e^-(rt)

OpenStudy (amistre64):

i got no idea what to do with that setup .... other than derive it and hope for the best

OpenStudy (anonymous):

yea alright well thanks for the help I have two tests tomorrow a physics and calc two test so just trying to be prepared

OpenStudy (amistre64):

if i had your material i might be able to come to an idea about what its asking for if it wants to use that formula

OpenStudy (anonymous):

its alright no worries

OpenStudy (amistre64):

so its akin to making regular payments to pay off a loan ....

OpenStudy (anonymous):

yea its like your paying off a 100,000 dollar loan only you are paying into an account to save up to 100,000

OpenStudy (amistre64):

that at least shows some computations that you can follow

OpenStudy (anonymous):

wow thank you thats awsome

OpenStudy (amistre64):

lol, google did it; not me :)

OpenStudy (anonymous):

well thank you for finding that

OpenStudy (amistre64):

youre welcome, with any luck it can be simple to parse

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