please....guess the value of the limit ( if it exists) by evaluating the function at the given numbers ( correct to six decimal places)
lim (when x approaches 2) ((x^2)-2x)/((x^2)-x-2)
the given numbers are : x= 2.5, 2.1 2.05, 2.01, 2.005, 2.001, 1.9, 1.95, 1.99, 1.995, 1.999

Question

please....guess the value of the limit ( if it exists) by evaluating the function at the given numbers ( correct to six decimal places) 
lim (when x approaches 2)  ((x^2)-2x)/((x^2)-x-2)
the given numbers are : x= 2.5, 2.1 2.05, 2.01, 2.005, 2.001, 1.9, 1.95, 1.99, 1.995, 1.999

anonymous · Answer

This exercise is trying to show you what a limit is. Essentially lim->2 of your function means that starting from any point, what answer (y value) does your function seem to be getting to. All you need to do is plug in the values that are given into your function. It looks like your function goes to 0/0 as it gets to 2 which means that in this form, the limit doesn't exist, but at any number above or below 2, it will give you a number.