Question

please help, ^2log 3 = a, ^3log 5 = b, so ^15log20=...

Answer 1

\[\log_{2} 3=a, \log_{3} 5=b, \log_{15} 20=??\]

Answer 2

so you need an answer in terms of a and b ??

Answer 3

yes please

Answer 4

can u draw the question?

Answer 5

if \[\log_{2} 3=a\] and \[\log_{3} 5 =b\] so \[\log_{15} 20 = ...\]

Answer 6

please answer in term a and b..

Answer 7

they are all different bases so you can't really combine anything...

Answer 8

it can be combined but it takes time...

Answer 9

you can say,
2^a *3^b = 15
so
\[= \log base(2^{a}3^{b}) 20\]

Answer 10

Would a=8?

Answer 11

\[2^{3}\] ??

Answer 12

no..

Answer 13

It would if 2^8 were 3

Answer 14

Ah thats the way it works! lol

Answer 15

i got it....

Answer 16

it's too long...

Answer 17

Lets have it!