Question

x + 4 2x+1
______ - ______
2x 6x How to do this?

Answer 1

Is this your question?

\[\frac{x+4}{2x}-\frac{2x+1}{6x}=0\]

Answer 2

There is no = 0, I just need to simplify it. Thanks!

Answer 3

Let's take LCM of 2x and 6x
\[2x=2\times x\]
\[6x=2\times 3 \times x\]
LCM= Product of common factors \(\times\) Product of uncommon factors

\[common factors= 2 \times x\]
uncommon factors=3
so we get
\[LCM=2x\times 3=6x\]
Now
\[\frac{x+4}{2x}-\frac{2x+1}{6x}\]
Multiply the numerator of first term by \(\frac{6x}{2x}=3\)
and multiply the numerator of second term by\(\frac{6x}{6x}=1\)
so we get
\[\frac{3\times (x+4)}{6x}-\frac{2x+1}{6x}\]
we get
\[\frac{3x+12-(2x+1)}{6x}\]
We get
\[\frac{x+11}{6x}\]

Answer 4

Wow I get it! Thanks so much!!!!!

Answer 5

Welcome :D

Answer 6

What if this problem is multiplying instead of subtracting?

Answer 7

Then Multiply the numerators separately and multiply the denominators separately

Answer 8

X+4 2X+1 3X +5
___ X _____ = ______ Correct??
2X 6X 12X

Answer 9

2X + 5
______ I bet this is right instead
12X

Answer 10

Cayenne
\[(x+4)(2x+1)=x(2x+1)+4(2x+1)=2x^2+2x+8x+1=>2x^2+10x+1\]
and
\[2x\times 6x= 12x^2\]

Answer 11

Sorry I made a mistake in the first one
\[(x+4)(2x+1)=2x^2+2x+8x+4=2x^2+10x+4\]

Answer 12

I get x times 2x = 2x squared, but x times 1 - how is that 2x?
Thanks

Answer 13

X+4 2X+1 2x^2+9X+4
___ X _____ = ______
2X 6X 12X^2

Answer 14

Sorry I made a mistake ,@phi 's answer is correct

Answer 15

Thanks you are grand! Very helpful...

Answer 16

Welcome @Cayenne

Answer 17

If I divided this same equation, I would invert the second fraction and multiply, right?

Answer 18

Yeah right:D

Answer 19

If you divide by a/b invert and multiply by b/a

Answer 20

Thanks!