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OpenStudy (anonymous):
Hello. I need to know how to solve: find the vertex of the equation: y=-3x^2-4x+9.plueze help!
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OpenStudy (saifoo.khan):
\[Vertex = (-\frac23, \frac{31}{2})\]
OpenStudy (anonymous):
thanks. would you show the work? I need to know step by step. thanks.
OpenStudy (precal):
there is a formula for the vertex.
OpenStudy (saifoo.khan):
Shortcut:
-b/2a.
\[-\frac{-4}{2(-3)}\to - \frac{-4}{-6} \to -\frac12\]
OpenStudy (saifoo.khan):
Now insert this value in the equation and find out the y-cordinate.
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OpenStudy (anonymous):
we just over this in class last night. so pardon me for saying...where in the equation do i insert it?
OpenStudy (precal):
in the original
OpenStudy (anonymous):
so I subsitute the x?
OpenStudy (precal):
yes
OpenStudy (anonymous):
okay thanks
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OpenStudy (saifoo.khan):
Have more problems?
OpenStudy (anonymous):
lots.
OpenStudy (saifoo.khan):
Post em!
OpenStudy (anonymous):
actually 4
OpenStudy (saifoo.khan):
Wow, we will take ages to do those.
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OpenStudy (anonymous):
lol
OpenStudy (saifoo.khan):
;)
OpenStudy (anonymous):
quadratic equations with solutions of \[{ 3/4 \-1/4}\] is defined as: write the equation
OpenStudy (saifoo.khan):
\[\frac34 , -\frac14\]That?
OpenStudy (anonymous):
yes
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OpenStudy (precal):
(x-3/4)(x+1/4)
OpenStudy (precal):
multiply it out
OpenStudy (anonymous):
okay
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