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let (x) be the first number, and let (y) be the second number: The first number is 3 LESS than the second number so x = y - 3 The twice the second number is 30 more than 4 times the first: 2y = 30 + 4(x) Now plug in the x = y-3 into the second equation to solve for (y) 2y = 30 + 4(y - 3) 2y = 30 + 4y - 12 -2y = 18 y = -9 Remember x = y -3, so now we can solve for (x): x = -9 - 3 x = -12 so your two numbers are -12 and -9
I concur with Hermeezey above.
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