Question

Use the quadratic formula to find the roots of the equation: x^2+x+10=0

Answer 1

quadratic formula
\[(-b \pm \sqrt{b ^{2}-4ac})/2a\]

\[ax ^{2}+bx+c\]

So a=1; b=1 and c=10

So you have \[(-1\pm \sqrt{1^{2}-(4)(1)(10)})/2(1)\]

This gets you\[-1/2\pm \sqrt{-39}\]

Since i equals a\[\sqrt{-1}\]

You have\[-1/2\pm i \sqrt{39}\]