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The population of a town decreased from 217,000 to 213,000 in 2 years. Assuming this trend continues what will the pop be in 3 additional years??
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12.000
is a linear function or exponential growth and decay..
Difference of 217,000 and 213,000 is 4,000. So the population decreased by 4000 in two years to 213,000 people. So for three additional years it will decrease by 213,000 – (4000+2000) = 207,000
I'll assume exponential find the decay constant \[P _{0} = 217000, t = 2\] \[ A = P _{0}e^{-kt}\]\ \[213000 = 217000e^{-2k}\] \[-2k = \ln(213000/217000)\] k = 0.009303 so the equation is \[A = 217000e^{-0.009303t}\] substitute t = 5 and solve to find the population
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