An archer shoots an arrow horizontally at a target with a speed of 52 m/s. The arrow drops 12 cm before hitting the target. What is the distance between the archer and the target
So what is the only force acting on the arrow after it is shot?
Gravity is the only force acting on it. Hence what is the only direction in which the arrow can accelerate after being shot?
In what direction does gravity act on the arrow? Horizontally, vertically?
vertically but how do i account for the drop of 12 cm?
vertically down, yes, with acceleration g. In time t, the arrow falls a distance of \[ y = \frac{1}{2}gt^2 \] and you are told that is 0.12 m. So you can solve for t. Now use that t to find how far the arrow has travelled.
So, time would be 0.156 s and distance would be like 8 meters?
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