Question

How do I solve an equation like this:

x^2+4x+4=0

Please include steps so I can finish my homework on my own :)

Thanks.

Answer 1

\[x^2+4x+4=0\]

Answer 2

quadratic formula :I

Answer 3

you have to find discriminant at first:
\[D=4^2- 4 \times 4 = 0\]
When D = 0, so \[x= (-4)\div2\]x = -2

Answer 4

Sorry, I'm not on discriminant yet so I have no idea what that means or how you got that :\

Answer 5

x = -2, but I'm not good at explaining, sorry.

Answer 6

then you can solve it by factoring
(x+2)(x+2)=0
x+2=0 or x+2=0 (it's the same so the answer also is the same)
x=-2

Answer 7

Thanks for the help :)