Question

Which value(s) of x should be excluded for the polynomial?
give me one minute and i will put up the equation
A. 3
B. 3 and -3
C. 4
D. 4 and -4

Answer 1

x^2-16/x^2-6x+9

Answer 2

You cannot divide by zero


So the denominator x^2-6x+9 can't be zero


If it were, then x^2-6x+9 = 0


Solve this for x


x^2-6x+9 = 0


(x-3)^2 = 0


x-3 = 0


x = 3


So when x = 3, the denominator is zero


So we must exclude 3 from the domain


So the answer is choice A

Answer 3

If you plug in 3, you get 0 in the denominator. 3 is an extraneous solution.