Mathematics
14 Online
OpenStudy (anonymous):
how to find the slope intercept form of y=-2x+2
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OpenStudy (agreene):
it is in slope intercept form:
y=mx+b
with:
m is slope
b is y intercept.
OpenStudy (anonymous):
so that means slope is -2 and y intercept is 2
OpenStudy (agreene):
yes.
OpenStudy (anonymous):
So as agreene said.... m is ur slope, so ur m in this equation is -2
OpenStudy (anonymous):
thanks so it would be graphed as (-2,2)
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OpenStudy (anonymous):
So, ur b is the starting point so it would be (2,-2)
OpenStudy (anonymous):
b = y intercept
OpenStudy (anonymous):
yea but dont i still have to have another point on my graph because it says i have to have a straight line so what would the other point be?
OpenStudy (anonymous):
sorry if im confusing
OpenStudy (anonymous):
can I help?
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OpenStudy (anonymous):
do you use a ti-84 calculator?
OpenStudy (anonymous):
yes you can help i really need it and no sorry :/
OpenStudy (anonymous):
I could still help give me a second
OpenStudy (anonymous):
okay thanks, i'll wait...
OpenStudy (anonymous):
formula for slope intercept form is y=mx+b
familiar with this?
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OpenStudy (anonymous):
so do you also need y intercept?
OpenStudy (anonymous):
yes im familiar with it and yes i also need the y intercept please
OpenStudy (anonymous):
for y intercept is y=-2(0)+2
since you are solving for y the x value should be zero.
OpenStudy (anonymous):
so the answer that i graph should be (-2,2)
OpenStudy (anonymous):
that's if you need to solve for both x and y intercept.
But it's better to see it by step so you could understand it better.
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OpenStudy (anonymous):
no i only need to solve for y intercep so the answer would be?
OpenStudy (anonymous):
So I will continue
OpenStudy (anonymous):
okay thanks..
OpenStudy (anonymous):
if only y intercept then is (0,2)
OpenStudy (anonymous):
the slope is -2
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OpenStudy (anonymous):
so i would have to graph it as (0,2) then rise -2 ?
OpenStudy (anonymous):
m=-2
y intercept is (0,2)
OpenStudy (anonymous):
yes but do you know how to graph the slope
OpenStudy (anonymous):
I'll draw the graph
OpenStudy (anonymous):
so that means i graph (0,2) then run over -2 ?
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OpenStudy (anonymous):
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OpenStudy (anonymous):
okay i graphed the 0,2 but how do igraph the -2