Mathematics
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OpenStudy (anonymous):
x^2 + 4x + 3 factor the solution?
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OpenStudy (anonymous):
Want to know a trick?
OpenStudy (anonymous):
yes please.
OpenStudy (anonymous):
times the first X * 3 (last number) = 3.. What factors of 3 add up to 4?
OpenStudy (amistre64):
(m-2)^2 + 4(m-2) +3 = 0
where x = m-2 .... maybe; then it might be m+2, i aint determined that part yet :)
OpenStudy (anonymous):
3 and 1
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OpenStudy (anonymous):
so your new middle numbers will be 3 and 1
OpenStudy (anonymous):
(x^2 +***3x***)(***1x***+3)
OpenStudy (anonymous):
So you factor out an X from the first one. x(x+3) and from the second one you can factor out a 1.. 1(x+3)
OpenStudy (amistre64):
m^2-4m+4
+4m-8
+3
-----------
m^2 -1 = 0
m = +-1
x = +-1 - 2 = -3,-1
dunno about the signs tho
OpenStudy (anonymous):
So you end up with x(x+3)+1(x+3)
The x and the 1 on the outside is your first pair (x+1)
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OpenStudy (anonymous):
then your second pair is (x+3)-- THEY ARE THE SAME
OpenStudy (anonymous):
So your answer would be (x+1)(x+3)
OpenStudy (amistre64):
woohoo; the roots are good :)
(x+1)(x+3) lol
OpenStudy (anonymous):
Questions?
OpenStudy (anonymous):
You had to factor that one by PAIRING
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OpenStudy (amistre64):
had to? nah
OpenStudy (anonymous):
Easier to understand.. Yes.
OpenStudy (anonymous):
:D
OpenStudy (amistre64):
perhaps :)