hwy does anyone know the derivative of f(x)=3x+5x^-1 ?
derivative of 3x = x derivative of 5x^-1 = -5x^-2
So collectively, \[\Large 3x+ 5x^{-1} \to -\frac{5}{x^2} +x\]
Holy cow. I never coulda figgered that on my own.
lol @ holycow
I get the one with the negative exponent. But doesn't the 3x derive into just 3? (1 x 3=3, and the x gets dropped...)?
Oh man! my mistake! holy cow!
that is what wass thing pinhead I was thinking, 3 - 5x^-2
i mean it's 3 not x.
haha!
Sowwie.
soooo, f'(x)= 3-5x^-2 ?
yes
Thanks so much, you two. I am so very bad at math. I can do other subjects really well, but math is holding me back
welcome to the website then - it may be a great resource
It sure seems like it! Another student friend o mine recommended it
now how can I factor this?
new question? if so do new post
I am trying to find critical numbers so i can find relative mins/max
f'(x)= 3-5x_2....I need to factor this, tosolve for 0, so I can find critical numbers...
f'(x)=3-5x^-2
how can I factor f'(x)= 3-5x^-2 ?
there's no way! How can I solve for X and find my critical values?
|dw:1331006796428:dw| look at it this way- does that hel you
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