Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

find g[h(x)] and h[g(x)] if g(x)=2x and h(x)=x^3+x^2+x+1

OpenStudy (precal):

g(h(x)) means sub h(x) into g(x) 2(x^3+x^2+x+1)

OpenStudy (precal):

h(g(x)) means sub g(x) into h(x)

OpenStudy (anonymous):

how would i set up the h[g(x)]? I have h(2x) so far

OpenStudy (precal):

everywhere there is an x just write (2x) put it in ( ) in case you have exponents.

OpenStudy (precal):

set it up and I will check it for you

OpenStudy (anonymous):

what would i fill in for h. for h(2x) it said the answer is 8x^3+4x^2+2x+1

OpenStudy (precal):

yes, you are correct

OpenStudy (anonymous):

so what would I plug in for h?

OpenStudy (precal):

you are done g(h(x)) is g(2x) that is your composition I would not write h(2x)

OpenStudy (anonymous):

I need to solve h(g(x))

OpenStudy (precal):

\[h(g(x))=8x^3+4x^2+2x+1\] nothing to do it

OpenStudy (anonymous):

I got it! in ever place in the formula x^3+x^2+x+1. i would plug in 2x for x

OpenStudy (anonymous):

thank you! i just couldn't figure out how they got that answer

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!