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MIT 6.002 Circuits and Electronics, Spring 2007 19 Online
OpenStudy (venomghost):

How can you solve a supernode problem like this? The values are: V=5V, I=3A, R1=3ohms, R2=5ohms You have to use the node method and e2 --> Ground (you have a Supernode too)

OpenStudy (venomghost):

Here it's the image of the circuit, You have to obtain e3, I didn't but like a blind guess I need som insight not just good luck xD thanks in advance any help will be apreciated

OpenStudy (anonymous):

First thing I did was redraw it so that the e2 GND point is on the bottom because my brain works that way. So then create the first equation using currents leaving the node(s):

OpenStudy (anonymous):

(Having some trouble with the equation editor)

OpenStudy (anonymous):

e1/3 + e3/5 + 3A = 0 e1 -e3 = 5V 2 equations, 2 unknowns

OpenStudy (venomghost):

no no @Tweedle_Dee that's the idea not redraw! solve it as it is :) that's where the problem lies

OpenStudy (anonymous):

Redrawing doesn't change the circuit, it just changes the way you look at it. My equations still apply.

OpenStudy (anonymous):

Sorry, I didn't have time to draw it before. This is what I meant by redrawing - just flipping it upside down. Nothing has changed except your perspective. |dw:1331085763933:dw|

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