i need help with a couple of promlems they are my last ones on this assessment plzzz help me

Question

anonymous · Answer

attachment

anonymous · Answer

the other 2 are   $$3\sqrt6  $$ $$6\sqrt{3}$$

anonymous · Answer

Ok, I believe you do it as follows: The equation to use is a proportion.  Let x = the altitude.  Then the proportion is 12/x = x/9.  To solve, cross multiply and get x^2 = 108.  Take square root of both sides and get x = $$\sqrt{108}$$.  The square root of 108 can be expressed as $$\sqrt{36x3}$$.  That simplifies to 6$$\sqrt{3}$$

anonymous · Answer

That should be 6$$6\sqrt{3}$$

anonymous · Answer

Arg!  Just

anonymous · Answer

$$6\sqrt{3}$$

anonymous · Answer

sorry having trouble with the equation thingy.

anonymous · Answer

dang i was close i got the numbers backwards lol 
thank u iv been trin to work them out

anonymous · Answer

Happy to help.

anonymous · Answer

so for the one i just posted recently would it be 6 or $$2\sqrt{8}$$

anonymous · Answer

Let me see if I can find that one...