A golf ball is hit from the ground with an initial velocity of 208 feet per second. Assume the starting height of the ball is 0 feet. How long will it take the golf ball to hit the ground?

Question

anonymous · Answer

Do you have any initial trajectory information (i.e. angle at which the ball is hit)?

anonymous · Answer

13secs

anonymous · Answer

h(t) = vo t - 1/2 gt^2

where vo = 208 ft/s and g = 32ft/s^2

h(t) = 208 t - 16t^2

when ball hits the ground h(t) = 0

208 t - 16t^2 = 0

=> 16 t ( 13 - t) = 0

t = 0 and 13 sec

0 s is the time when ball is hit from the ground

ball hits the ground after 13 s

amistre64 · Answer

your vo t is off

amistre64 · Answer

vo sin(a) t would be the upward force involved in this so there are at most 2 answers

amistre64 · Answer

or maybe infinitely many ...

amistre64 · Answer

we need either a distance; or some other peice of information