If g is any real number, then g3 0.

Which of the following is a counterexample to the assertion above?

A. g = 6
B. g = -6
C. There is no counterexample to this assertion.
D. g = 0

Question

If g is any real number, then g3 > 0.

Which of the following is a counterexample to the assertion above?

 	 A.	g = 6
	 B.	g = -6
	 C.	There is no counterexample to this assertion.
	 D.	g = 0

anonymous · Answer

-6^3 = -216 which is not > 0.
0^3 = 0 which is not > 0.

anonymous · Answer

i dont get it

anonymous · Answer

Well the rule is stating that for any real number g, g^3 is going to be greater than 0. Is that right?
So a counterexample is one which goes against what the rule says - i.e. any real number for g that, when raised to the power of 3, is not going to be greater than 0.

anonymous · Answer

SO WHATS THE ANSWER THEN?? :/