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find the roots of the polynomial equation 2x^3+2x^2-19x+20=0
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-4
what are also the real and complex numbers
but what are they for this equation
the roots are as follow, x= -4, x = (6+\[\sqrt{-4}\])/4, x = (6-\[\sqrt{-4}\])/4
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as you cant take sq root of minus thereofre we instead of sqrt of -4 will be written as 2i where i is sqrt of -1
you can write the roots x = -4, x=( 6+2i)/4, x=( 6-2i)/4
the first root is a real number whereas the other two are complex
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