Clarence has to take 2 different kind of pills (Pill A, Pill B). Both pills look exactly the same (same weight, color, shape, size, etc…) If he takes more than 1 pill of the same kind per day, he will die. Furthermore, if he doesn’t take 1 Pill A, and 1 Pill B every day, he will also die. Clarence is on a limited budget, and since the pills are extremely expensive, he can’t throw any of them away. One day, he got distracted and by mistake put 3 pills on the table. Since both pill types look identical, he’s not sure which pill is which.
How can he manage to take the pills without any further dire consequences and yet save the extra pill?
This doesn't really look like a maths question... tricky though!
Hmm, not gonna lie I've been staring at this for like ten minutes. So... does he know that both types of pills are on the table? Could all three be the same one?
no there are 2 B pills and 1 A pill. but he can't distinguish which one is A or B.
is this probability related question?
No, kind of like a logic question. Is there any way he could survive in this situation where there are 2 B-pills and 1 A-pill in his hand and he cannot eat all 3 because he would die and he cannot stop taking any pill because he would still die.
he must eat 1 A-pill and 1 B-pill per day in order to survive. Too much or too less, he will die
the probability of getting 1 A and B pill out of three (3) pills is 2/3. . therefor his chance to live is 2/3.
ok thanks!!!
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