Mathematics
8 Online
OpenStudy (anonymous):
please help: Use the substitution method to solve the linear system.
1/2x+y=2
2x+3y=9
different problem
1/3x+5/6y=1
1/2x-y=1
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OpenStudy (precal):
@Desiree97 would you like me to show you how to do the first one?
OpenStudy (anonymous):
sure
OpenStudy (precal):
ok lets take (1/2)x+y=2
rewrite it to say y=?
tell me what that would be
OpenStudy (anonymous):
y=1/2x+2
OpenStudy (precal):
when you move (1/2)x to the other side, you need to switch the sign to negative
so
y=2-(1/2)x
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OpenStudy (precal):
Now sub this into the second equation
OpenStudy (precal):
what do you get?
OpenStudy (anonymous):
i have x-4=9 so x = 13
OpenStudy (precal):
no, 2x+3(2-(1/2)x)=9
solve for x tell me what you get
OpenStudy (precal):
waiting........
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OpenStudy (anonymous):
x=5
OpenStudy (precal):
no
2x+3(2-(1/2)x)=9
distribut 3
2x+6-(3/2)x=9
-6 -6
(4/2)x-(3/2)x=3
(1/2)x=3
mulitply 2 to both sides
x=6
OpenStudy (precal):
now that you know x=6
use 2x+3y=9 sub for x and tell me what y is
OpenStudy (precal):
waiting.....
OpenStudy (anonymous):
y=13
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OpenStudy (precal):
2(6)+3y=9
solve for y....... your y value is incorrect
OpenStudy (anonymous):
y =7
OpenStudy (precal):
want to show some steps because once again you are incorrect
OpenStudy (anonymous):
yeah show me some steps
OpenStudy (precal):
no, I would like you to show me some steps
first step is 2(6)+3y=9
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OpenStudy (anonymous):
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