Question

differentiate y= (x^2+4x+3)/x^(1/2)

Answer 1

best bet is to divide each term by
\[x^{\frac{1}{2}}\] by subtracting the exponents, then use the power rule for each term

Answer 2

\[y=x^{\frac{3}{2}}+4x^{\frac{1}{2}}+3x^{-\frac{1}{2}}\] and then power rule three times

Answer 3

how did you get the 3x^(-1/2) if the 3 does not have an X?? im confused

Answer 4

y= (x^2+4x+3)/x^(1/2)
y=x^2/x^(1/2)+4x/x^(1/2)+3/x^(1/2)
y=x^(2-1/2)+4x^(1-1/2)+3x^-1/2
y=x^3/2+4x^1/2+3x-1/2
now when u diff y'
y'=3/2x^1/2+4*1/2*x^-1/2-3/2x^-3/2
y'=3/2x^1/2+2x^(-1/2)-3/2x^-3/2