Question

If 30.0mL of 0.150M CaCl2 is added to 15.0mL of 0.100M AgNO3, what is the mass in grams of AgCl participate? Help!

Answer 1

30.0mL = 0.0300L CaCl2
15.0mL = 0.0150L AgNO3

0.150M*.0300L = .0045 mols of CaCl2
0.100M*0.0150L = 0.0015 mols of AgNO3

To go further you need the balanced chemical equation. When you have that pick a reactant then take that and divide by the number of mols produced in the chem equation. Then multiply by the molec weight of AgCl (143.32 g/mol) to get the weight produced.

You will have to do this for both reactants as one could be a limiting reactant. In that case take the lesser of the 2 numbers and that will be your answer

Answer 2

CaCl2 + 2AgNO3 --> 2AgCl + Ca(NO3)2 giving you a molar ration of 1CaCl2:2AgCl. Looking at the math provided by Oh_hai, I can see that the silver nitrate is the limiting reactant.