How do I find the area of a regular pentagon?
Any information about the regular pentagon given?
The full question was Find the area of a regular pentagon with side 6 cm.
given the measure of the side (s) , we can find the area. from the center to the vertex of the regular pentagon, we can make 5 equilateral triangles,therefor the formula will,. area = 5 (1/2bh)
Area of regular pentagon with side a \[\frac{5a^2}{4}\tan(54)\]
54 in degrees
Wwell the possible answers are 76.6 cm^2, 61.9 cm^2 ,45.2 cm^2, or 123.9 cm^2
61.9
are you allowed to use calculator?
therefor the area = 5(1/2 (6)(3sqrt3)
Yes I can use a calculator but I'm still confused on finding how to do it
thank you for all the help everybody by the way its appreciated
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