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Directrix (directrix):
Any information about the regular pentagon given?
OpenStudy (anonymous):
The full question was Find the area of a regular pentagon with side 6 cm.
OpenStudy (anonymous):
given the measure of the side (s) , we can find the area.
from the center to the vertex of the regular pentagon, we can make 5 equilateral triangles,therefor the formula will,.
area = 5 (1/2bh)
OpenStudy (anonymous):
Area of regular pentagon with side a
\[\frac{5a^2}{4}\tan(54)\]
OpenStudy (anonymous):
54 in degrees
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OpenStudy (anonymous):
Wwell the possible answers are
76.6 cm^2, 61.9 cm^2 ,45.2 cm^2, or 123.9 cm^2
OpenStudy (anonymous):
61.9
OpenStudy (anonymous):
are you allowed to use calculator?
OpenStudy (anonymous):
therefor the area = 5(1/2 (6)(3sqrt3)
OpenStudy (anonymous):
Yes I can use a calculator but I'm still confused on finding how to do it
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OpenStudy (anonymous):
thank you for all the help everybody by the way its appreciated