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How would one differentiate the following: 2x+3/√(1-2x)
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You can use the quotient rule.
Are you familiar with that?
yes I am familiar with this
so u = 2x+3 u' = 2 v = √(1-2x) v' = -1/√(1-2x)
The quotient rule says dy/dx = (u'v - uv')/v^2
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ok and from there I begin to distribute, correct?
u can do it with quotient rule
Thats it follow (u'v - uv')/v^2
|dw:1331119146075:dw| use this this is the division rule
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