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how would i use the quadratic equation for x^3+17x^2+72x-90 to find the other two zeros after i have already found one
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factor it
the question isnt asking me to factor
divide this equation by (x-1) you will get x^2+18x+90 then factorise it you will get remaining 2 factors
the first zero i got was 1. so i would use -1 right?
no divide your equation by (x-1) because first zero you got at x=1 so (x-1)=0 after dividing you will get second order eqution solve it you will get the required solution
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|dw:1331140292567:dw| is that how i would set it up?
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