-(1/4)=sinx solve for x. do I use special triangles?
x = Sin^-1(-1/4)
-14deg
no you use a calculator for this one
if it was (1/sqrt2)= sinx, i could use special triangles?
use expansion formula for sin inverse of x
If sinx - 1/4 = 0, you are looking for values of x where sinx = 0.25. sinx is positive in the interval from 0 to pi (and zero at 0 and pi) and negative from pi to 2pi, so your solutions will be in the first interval. So, check out arcsin0.25 in a table and look for values between 0 and 1. Or, use an interesting fact about sinx, which is that for values of x near zero, sinx is nearly equal to x in this interval. That is why lim as x ->0 of sinx/x is one. So, by symmetry, your answers are roughly 0.25 and pi - 0.25 (3.14-0.25 = 2.89)
ooh thanks hah thats really helpful :)
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