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What is 23 expressed as a difference of two perfect squares?
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\[\huge {23= 12^2-11^2}\]
11 isn't a perfect square. it has to be the sum of two PERFECT squares.
oh 23=144-121
144 is square of 12 121 is square of 11
and they are perfect squares?
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the question is: "Every odd prime can be expressed as the difference of two perfect squares in one and only one way. Find the way for 23."
A perfect square no. is the result of product of a number by itself . 4 is a perfect square cause 2*2=4 similarly 121= 11*11 144=12*12
awesome thanks so much !
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