I need help with this word problem: Army requirements call for 55 coffee grounds/quart of coffee. One barrel contains coffee with 67.5 grounds/quart and another contains coffee with 45/quart. How many quarts of each to make 18 quarts with the right amount of grounds?
Let's start by assigning the letter x to the amount of 67.5 grounds/qt coffee. Therefore (18-x) is the amount of 45 grounds/quart we'll use. Since we want 18 quarts of 55 ground/quart coffee, you'll want to multiply those two numbers. (See the keyword OF?) Set up the equation like so: \[67.5x+45(18-x)=990\] Using the distributive property, that will become \[67.5x+810-45x=990\] Subtract the 45x from the 67.5x. \[22.5+810=990\] Subtract 810 from both sides- \[22.5=180\] Divide 180 by 22.5. \[180\div22.5=8\] x=8 So we have 8 quarts of 67.5 ground/quart coffee and (18-8=10) 10 quarts of 45 ground/quart coffee. :)
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