Question

2x^-3

Answer 1

\[2/\sqrt[3]{x}\]

Answer 2

oops 2/x^3

Answer 3

help me please chris

Answer 4

when you have a negative exponent you just drop the value to the denominator

Answer 5

x^-3 is the same as 1/x^3

Answer 6

so 2(1/x^3)=2/x^3

Answer 7

i guess thats what you are looking for since you give no further directions

Answer 8

what is it you are trying to do?

Answer 9

horizontal translation equation

Answer 10

sec

Answer 11

did they give you a point?

Answer 12

no I just need to make up an equation and graphing

Answer 13

I am confused because normally for a horizontal translation a point is given

Answer 14

I have to create a horizontal function coming up with the points

Answer 15

so in other words i can plug 0 in for x and find my own point?

Answer 16

yes

Answer 17

well x cant be 0 so lets do 1 then

Answer 18

ok

Answer 19

f(1)=2/(1)^3=2

Answer 20

so if x = 1 y = 2

Answer 21

2=2/(1-a)^3
2=2/1-a^3
2(1-a^3)=2
1-a^3=1
-a^3=0
a=0
which this would not change the equation, not having a point given confuses me >.<

Answer 22

if you used 2 for x your answer would be different

Answer 23

y=1/4 so

1/4= 2/(2-a)^3

Answer 24

14=2/(8-a^3)

Answer 25

1/4(8-a^3)=2

Answer 26

(1/4(8-a^3)=2)4

Answer 27

8-a^3=8

Answer 28

wait wait
ok, I'm confused now too without an point given. Ok so example : f(X)= 4^3-x is horizontal equation. How would that be solved?

Answer 29

-a^3=0

Answer 30

so a agaon would = 0

Answer 31

meaning it would touch the line?

Answer 32

can't you plug in x value's ?

Answer 33

meaning the new equation which would be y=2(x-a)^3 would not be a change

Answer 34

y=2(x-0)^-3

Answer 35

if a is 0 there was no shift

Answer 36

ooh ok

Answer 37

this is why i dont like it when they do not give me a point to work with >.<

Answer 38

O.o me either