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Confusion! Let f(x)=x^2+5x, g(x)=6-2x, h(x)=2/x-3; find the following value. f(6)-4=
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f(6) -4=((6)^2+5(6))-4= 36+30-4= 62
Whoa thanks! Can you please tell me how you got that?
Oh wait, just plug in?
Yeah f(x) is x^2+5x. So f(6) is plugged into the x giving (6)^2+5(6)= 36+30=66. The problem asks for f(6)-4 so that is 66-4=62
Yeah
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people don't like to type so they abbreviate with things like f(x) it means go look for the definition, and replace x with whatever number I put in example f(2) means plug in 2 for x. saves typing.
Oh I see. But I tried this one out: Let f(x)=x^2+5x, g(x)=6-2x, h(x)=2/x-3; find the following value. f(-3). I got -24, is this correct?
9-15= -6
-3*-3 is +9
(-3)^2+5(-3)= 9-15=-6
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OH o.k. Now I understand. Thanks guys! :)
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