Question

Could someone explain how to find the answer to this problem u=vw+z, for v

Answer 1

u=vw+z
u-z=vw
\[\frac{u-z}{w}=v\]

Answer 2

thanks for your help, trying to help my son and not doing very well

Answer 3

you're welcome.

Answer 4

are you up for another one, these have me stumped fg-9h=10j, for g

Answer 5

sure... I'll add some narration on this one too
fg-9h=10j
first add 9h to both sides
fg=10j+9h
then to isolate the g, divide both sides by f
\[g=\frac{10j+9h}{f}\]

Answer 6

thanks again, still working on the whole concept

Answer 7

just some basics... you are trying to isolate the variable you are solving for, or get it by itself on one side.
That involves performing operations that remove the other variables or constants from the side the desired variable is on. For instance is something is added to the variable you wish to isolate, you need to subtract it from the variable.
Anything you do to one side has to be done to the other side.

Answer 8

this is the current problem could you just tell me if we are doing this correctly, the problem is r=2/3t+v, for t; we have subtracted 2/3 from both sides v=2/3-r, divide both sides by v 2/3-r over v=v

Answer 9

so first of all you have two terms on the side with the variable you want to isolate with this problem. The terms are 2/3t and v. The first item you will want to remove is the item that *does not* contain the variable you want to isolate. In this case it is v
since it is beint added to your t-term, you need to subtract it, and to keep everything equal you have to subtract it from both sides.
\[r=\frac{2}{3}t+v\]
\[r-v=\frac{2}{3}t+v-v\]
Of course v-v =0 so we have successfully isolated the t-term
\[r-v=\frac{2}{3}t\]
So we have isolated the t-term, but t is still not by itself. It is being multiplied by 2/3 so we have to divide it by 2/3. Remember, dividing by a fraction is the same as multiplying by its reciprocal (the fraction upside down) So,
\[\frac{3}{2}(r-v)=\frac{2}{3}t*\frac{3}{2}\]
which gives us
\[\frac{3}{2}(r-v)=t\]

Answer 10

Now I don't know what form your son's teacher would prefer to see the answer. To me the answer above is complete because t is isolated. However some teachers may want to see it simplified which means the answer above is the same as
\[\frac{3}{2}*\frac{r-v}{1}=t\]
which gives\[\frac{3(r-v)}{2}=t\]
and it can be simplified even on step further by factoring in the 3
\[\frac{3r-3v}{2}=t\]

Answer 11

how do you know which number to wipeout if there is two numbers in the equation

Answer 12

If you are trying to isolate a variable, you are pretty much going to want to get rid of everything from the side the variable you want to isolate is on. I'm not totally sure I fully understand your question though. An example may be helpful if you have one.

Answer 13

\[=-3, for a \]\[10ac-x \over 11 \]

Answer 14

what's the significance of the -3?
is this supposed to be \[\frac{10ac-x}{11}=-3\]?

Answer 15

yeah that's right, I was having problems with the buttons

Answer 16

ok... so in this one at the start you want to isolate the numerator first
so you are getting rid of the denominator, and a denominator means divided by so to get rid of it, you have to multiply both sides by 11 so we get
10ac-x=-33

Answer 17

I have to head home, will be an hour or so before I get back. I'll leave the rest of this one for you to try to finish. If you are still having trouble, just post a new thread, I'm sure someone will help, and I will peek in when I get home.

Answer 18

thanks for all your help

Answer 19

you are very welcome