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Find the domain and range. y=2/3sqrtx
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\[y=\frac{2}{3\sqrt{x}}\] is this how it is written?
Domain is all the xs you could put in the equation and range is all of the possible ys.
the domain is not all reals
the denominator can't equal zero because dividing by 0 is undefined, and also taking the square root of a negative number results in a nonreal answer. So your domain is {x|x>0}
as for the range, 0 is not in the range because there is a horiztonal asymptote at the x-axis or y=0
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also the output will never be negative because the sqrt(x) is positive for all real numbers in the domain
so the range is (0, infinity)
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