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Mathematics 17 Online
OpenStudy (anonymous):

see attachment

OpenStudy (anonymous):

OpenStudy (anonymous):

Confusing.

OpenStudy (dumbcow):

Find angle C, then use Law of Sines

OpenStudy (anonymous):

apply law of sines. .

OpenStudy (anonymous):

Tan?

Directrix (directrix):

Only right triangle trig for this problem so I was told.

OpenStudy (dumbcow):

\[\frac{BC}{\sin 42} = \frac{325}{\sin C}\]

OpenStudy (anonymous):

I think tangent could work too

OpenStudy (anonymous):

angle C= 180 -(110+42) =38

OpenStudy (anonymous):

substitute value of angle C to the equation dumbcow given. . .

OpenStudy (anonymous):

Sorry my mouse was spazzing out but you get the idea :P

OpenStudy (anonymous):

Why not Tangent?

OpenStudy (dumbcow):

you could use tangent by splitting angle B into a right angle but thats just more work ?

OpenStudy (anonymous):

yeah, agree @ dumbcow. .

OpenStudy (anonymous):

I'm pretty sure she'not supposed to know the law of sines.

OpenStudy (anonymous):

I don't know it

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

value of angle C is 38. . plug it to the equation|dw:1331195313621:dw| compute. .

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