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Mathematics 11 Online
OpenStudy (anonymous):

Describe the domain and range of the function: g(x,y) = y / (squarert of x)

OpenStudy (anonymous):

\[g(x,y)=y/\sqrt{x}\]

OpenStudy (anonymous):

For the domain, the answer would be x >0 right?

OpenStudy (anonymous):

and the range would be all real numbers for y?

OpenStudy (amistre64):

domain is the anding of teh x and y parts Dy = all reals Dx = greater than 0 so the right portion up to but not including the y axis (the x=0 axis)

OpenStudy (amistre64):

range is then the z axis

OpenStudy (amistre64):

|dw:1331214139820:dw|

OpenStudy (amistre64):

|dw:1331214172866:dw|

OpenStudy (amistre64):

your range is not restricted by anything; the y up top makes it + or - and the bottom is any real number as well so we dont really go bad in it

OpenStudy (amistre64):

the result that is :)

OpenStudy (amistre64):

\[Z_r:\frac{Y_r=(-inf,inf)}{X_r=(0,inf)}=(-inf,inf)\]

OpenStudy (anonymous):

^Is that answer for the range or the domain, or both?

OpenStudy (amistre64):

the domain is the area of the xy plane; D = {(x,y) | x>0 and yeR} the range is all possible results from as a result of the domain it just so happens that f: D -> R is pretty much unrestricted along the z axis

OpenStudy (amistre64):

http://web.monroecc.edu/manila/webfiles/calcNSF/JavaCode/CalcPlot3D.htm this gives a neater pcture of it

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