Describe the domain and range of the function: g(x,y) = y / (squarert of x)
\[g(x,y)=y/\sqrt{x}\]
For the domain, the answer would be x >0 right?
and the range would be all real numbers for y?
domain is the anding of teh x and y parts Dy = all reals Dx = greater than 0 so the right portion up to but not including the y axis (the x=0 axis)
range is then the z axis
|dw:1331214139820:dw|
|dw:1331214172866:dw|
your range is not restricted by anything; the y up top makes it + or - and the bottom is any real number as well so we dont really go bad in it
the result that is :)
\[Z_r:\frac{Y_r=(-inf,inf)}{X_r=(0,inf)}=(-inf,inf)\]
^Is that answer for the range or the domain, or both?
the domain is the area of the xy plane; D = {(x,y) | x>0 and yeR} the range is all possible results from as a result of the domain it just so happens that f: D -> R is pretty much unrestricted along the z axis
http://web.monroecc.edu/manila/webfiles/calcNSF/JavaCode/CalcPlot3D.htm this gives a neater pcture of it
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