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Write the function in vertex form and identify its vertex. g(x) = x2 - 10x + 11
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same idea as the last one. lets see if i can do it without making a mistake
\[-\frac{b}{2a}=\frac{10}{2}=5\] and \[g(5)=5^2-10\times 5 +11=25-50+11=-25+11=-14\] so vertex is \[(5,-14)\] and vertex form will be \[g(x)=(x-5)^2-14\]
you can check that this is correct by multiplying out \[(x-5)^2-14\] and see that you get \[x^2-10x+11\]
got it!
always works like this. you can also "complete the square" if you like, but it is unnecessary
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