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Mathematics 15 Online
OpenStudy (anonymous):

simplified form of 9x^2+30x+25 over 3x+5 3x-5 with restriction x ≠ 5/3 3x+5 with restriction x ≠ 5/3 3x-5 with restriction x ≠ -5/3 3x+5 with restriction x ≠ -5/3

OpenStudy (anonymous):

factor the top part first

OpenStudy (campbell_st):

\[(3x + 5)^2/(3x + 5) = (3x + 5)\]

OpenStudy (anonymous):

Your other two options are to divide using long division or use synthetic division.

OpenStudy (anonymous):

I get 3x+5 with restriction x ≠ 5/3 .... am I right?

OpenStudy (anonymous):

Yes, that's the answer. The only reason you have the restriction is that dividing by zero is undefined.

OpenStudy (anonymous):

ok, thank you!!!!

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