Question

y = x² + 3x – 4
y = 2x + 2

(–3, 6) and (2, –4)
(–3, –4) and (2, 6)
(–3, –4) and (–2, –2)
no solution

Answer 1

equate the two equations

2x + 2 = x^2 +3x - 4

then x^2 +x -6 = 0

solve by factorising

(x - 3)(x +2)=0

then x = 3 or -2

Answer 2

substitute each x value to find the corresponding y

Answer 3

None of them are matching up...unless a mistake was made.

Answer 4

x^2 +x -6 = 0
(x+3)(x-2) = 0
x = -3,2

Answer 5

Another goof up by me