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5x^2 + 15x
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5x(x+3)
5x^2=15x Move the 15x over to the other side. Now you have: 5x^2 - 15x = 0 Does this look more familiar? More like a quadratic? Now try factoring out the monomial, which is in this case 5x. 5x (x - 3) = 0 What will make 5x = 0? 0. What will make x-3 = 0? 3. So your solution set is... {0, 3} And, yes, they do each work when you plug them back in!
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