Question

HELPPPP MEE PLEASEEEEE!!!!!

Answer 1

what formula are you using?

Answer 2

Trigonometry

Answer 3

use Pythagoras theorem

Answer 4

i tried using the pythag. theorem and i didnt get any of the answers listed.

Answer 5

can you show me what you did....

Answer 6

A^2+6^2=12^2
A^2+36=144
SUBTRACT 36 from both sides
A^2=(Square root) 108

Answer 7

no you are right...

Answer 8

squareroot (108)
where 36 * 3= 108

Answer 9

you can squareroot that 36 out
whats the square root of 36?

Answer 10

6

Answer 11

yeah and you still have that square root of 3 left right?

Answer 12

6 * squareroot3

Answer 13

ohhhhh okay, i got it! thank you!

Answer 14

Ok don't forget to simplify things...most of the answers will be simplified.

Answer 15

If you are doing trig, then they want you to learn about 30-60-90 triangles. In these triangles, the short side (opposite 30 deg angle) is 1/2 the hypotenuse. The longer leg (that is not the hypotenuse) is sqrt(3)* shorter leg.

Here the shorter leg is 6, so the longer leg is 6sqrt(3)

Of course, pyth works, but if they did not give you the shorter leg=6, you would have been in trouble. But if you know trig, you would know it was 12/2 = 6, and so x= 6 sqrt(3)

Answer 16

@phi So in order to do that you have to know that it's a 30-60 right triangle but at this point you can use cos sin and tan to figure out the other lengths right? Even if you are given just one side you can figure it out using sin and cos right?

Answer 17

yes. sin(30)= cos(60)= 1/2 and cos(30)= sin(60)=sqrt(3)/2,

Answer 18

and, of course, you must know the definitions (which sides are in the ratio) for sin and cos