Question

simplify this: (x^-3y^3)^2/x^5y^6

Answer 1

(x^(-3)y^(3))^2/(x^(5)y^(6))

Answer 2

yes

Answer 3

To solve this it is as simple as
(x^(-3)y^(3))^2 = (x^(-3)y^(3))(x^(-3)y^(3)) = (x^(-3)y^(3)x^(-3)y^(3))
(x^(-3)y^(3)x^(-3)y^(3))
= x^(-6)y^(6)


Remember the rule x^(-1) = 1/x

so

y^(6)/x^(6) / (x^(5)y^(6))/1

=

y^(6)/x^(6)y^(6)x^(5)
=

1/x^(11)

Answer 4

y^(6)/x^(6)y^(6)x^(5)
=
y^(6)y^(-6)/x^(6)x^(5)
=
y^(0)/x^(6)x^(5)
=
1/x^(6)x^(5)

remembering a^(0) = 1, where a =/= 0

Answer 5

do you understand?

Answer 6

the first part I you just have to remember that x^(-3)*y^(3) is 1 term so when it is squared it is just (x^(-3)y^(3))(x^(-3)y^(3)) as x^(2) = x * x

Answer 7

ok

Answer 8

so I will assume you get it now :)

Answer 9

what i s the answer?

Answer 10

I posted it in my first solution

Answer 11

-_-

Answer 12

ok i see i confused my self lol

Answer 13

Yeah I wasn't really clear in my math sorry I just wanted to explain the rules as I went along