Question

calculate the derivative tln(t^(2)+1)

Answer 1

t*ln(t^(2)+1)
use the product rule and then apply derivative of ln(x) and u gotta take derivative of of (t^2+1 then u get

=t * 1/(t^2+1)* 2t+ln(t^(2)+1) *1

Answer 2

no chain rule?

Answer 3

take derivative of of (t^2+1) is the chain rule

ln(x) what ever is in side the parameter u gotta take derivative too
let say ln(t^(2)+1) u take derivative of ln(t^(2)+1) u get 1/t^(2)+1) times the derivative of whatever is inside parenthesisin this case t^(2)+1) = 2t