I'm trying to compute growth time.The problem says to use the natural logarithm on both sides of the equation "and use the property 1n M^p = p 1n M" How does that work? The equation is
1n 1.2 = n 1n 1.0075
Please help! Thx :)

Question

I'm trying to compute growth time.The problem says to use the natural logarithm on both sides of the equation "and use the property 1n M^p = p 1n M" How does that work? The equation is 
1n 1.2 = n 1n 1.0075
Please help! Thx :)

dumbcow · Answer

is this the equation:
$$\ln (1.2)  =n*\ln (1.0075) $$

anonymous · Answer

Yes, then the next step shows $$n=\ln 1.2\div \ln 1.0075$$
I'm trying to apply this equation in the book to a homework question. Thanks for helping out!

dumbcow · Answer

don;t know what you really need help with

dumbcow · Answer

the general exponential growth function is :
$$P(t) = P_{0}*b^{kt}$$

anonymous · Answer

I don't know what that means. Thanks anyway
I'm trying to understand what "use the property 1n M^p = p 1n M" when using the base e logarithm