Question

\[What's~~~f'~~~ of ~~~ \sin^2x^2+\cos^2x^2~~~~~~?\]

Answer 1

In other words, differentiate it.

Answer 2

I think I got a wrong answer... I got
4sinx^2cosx^2 +4cosx^2sinx^2

Answer 3

Or, is it -4cosx^2sinx^2?

Answer 4

\[2sinx ^{2}\cos x^{2}2x+2cosx ^{2}(-\sin x^{2})2x\]

Answer 5

Yes it is -4cosx^2sinx^2

Answer 6

My text book says the answer is 0? Is it wrong?

Answer 7

actually its 0

Answer 8

wolfram got problem,
sin^(2)x^(2)+cos^(2)x^(2)

(d)/(dv) =cos(v)

(d)/(dx) =4xsin((x^(2)))cos((x^(2)))

(d)/(dv) =-sin(v)

(d)/(dx) =-4xcos((x^(2)))sin((x^(2)))

(d)/(dx) =4xsin((x^(2)))cos((x^(2)))-4xcos((x^(2)))sin((x^(2)))

0

Answer 9

Oh. So, if you minus what you and I differentiates, the answer is 0?

Answer 10

differentiated*

Answer 11

yes

Answer 12

Ok, great :) Thanks