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(4, -5) and that passes through (-1, 3)?
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I got 1/6 = a, but I don't know how it's final answer is f(x) = 1/6(x^ - 7)
What are you finding with the two points? Slope? Equation of a line?
equation of the parabola
with x- intercepts
Is it possible for just two points to determine a parabola? Are these special points, maybe the vertex and some other point on the parabola. I don't recognize this < f(x) = 1/6(x^ - 7) >> as the equation of a parabola.
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Do you have instructions for the problem that you could post here?
well this is what I did f(x) = a(x-r)(x-s) f(-3) = a(1-4)(1+5) -3 = a(-3)(6) -3/18 = -18/18 a 1/6 = a
can u post the whole question?
Determine the equation of the parabola with x- intercepts.
x intercepts 4 and -5?
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