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Mathematics 10 Online
OpenStudy (anonymous):

How many triangles can you form if you draw all the diagonals of a hexagon? 12 14 16 18

OpenStudy (carniel):

Hexagon = 6 sided figure so it should be 12 triangles

sam (.sam.):

6 triangles (because a hexagon has 6 sides).

OpenStudy (carniel):

Thats not a answer choose and thats wrong

sam (.sam.):

If you're talking about drawing triangles inside a hexagon you end up with 4 because the formula is ,number of sides -2

OpenStudy (anonymous):

@.Sam.: How can it be 4?. there are 9 diagonals

OpenStudy (anonymous):

The answer is 4 when you draw all diagonals from only one vertex.

OpenStudy (anonymous):

First choose a diagonal. In 9 ways. Then choose any other point. 4 points left. Can be chosen in 4 ways. Therefore. 36 trangles/3 because of repitition.

OpenStudy (anonymous):

Answer is hence 12.

OpenStudy (anonymous):

REpitition is because you can land up with the same triangle in three different ways (through the given points/ diagonals again)

OpenStudy (carniel):

Yes Sid I said that. They keep saying wrong answers....

OpenStudy (anonymous):

Carniels right man. :D

OpenStudy (carniel):

^_^ Thanks Sid

sam (.sam.):

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OpenStudy (carniel):

Sam you you didn't even go to the other ones...

sam (.sam.):

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OpenStudy (anonymous):

Dude. Thats one vertex. Actual way to look at this is. 6 points. To make a diagonal you need two points. Therefore 6C2 ways = 15. - 6 as the sides will also come in our calculation.

OpenStudy (carniel):

Btw you choose one to start from not all the others.

OpenStudy (anonymous):

Thats Correct. 9 diagonals it is. :)

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