Question

Which quadratic equation has a vertex of (0, 5)?

Answer 1

x^2-2x+1=0

Answer 2

Well, there are quite a few that might qualify, but \[y=ax^2+5\]with \[a \in \mathbb{R}\]seems to be a general statement of most of the suspects.

Answer 3

Further note: \[a \in \mathbb{R}/\left\{ 0 \right\}\]

Answer 4

Vertex form is y = (x - h)^2 + k
where (h, k) is the vertex
so for vertex (0, 5)
y = (x - 0)^2 + 5
y = x^2 + 5